Answer:
Explanation:
Part A
Since, all angle formed at point F lie on a straight line CE.
Therefore, sum of angles ∠AFE, ∠AFB, ∠CFB will be 180°.
(7x + 4) + (8x + 6) + (6x + 2) = 180
21x + 12 = 180
21x = 168
x = 8
Part B
Two lines CD and AE intersect each other at point F.
Therefore, ∠AFE ≅ ∠DFC [Vertically opposite angles]
m∠CFD = (7x + 4)°
= 7(8) + 4
= 60°
Since, all angles formed at point F on a straight line AD are linear angles,
m∠AFB + m∠CFB + m∠CFD = 180°
(8x + 6) + (6x + 2) + m∠CFD = 180°
14x + 8 + m∠CFD = 180
m∠CFD = 172 - 14x
= 172 - 14(8)
= 172 - 112
= 60°