Question

You have 1.2 x 10^25 particles of NiCO3. How many grams are present?

Answer 1

2365.0 g

Step-by-step explanation:

First we convert 1.2 x 10²⁵ particles into moles, using Avogadro's number:

• 1.2 x 10²⁵ particles ÷ 6.023x10²³ particles/mol = 19.9 mol

Then we convert 19.9 moles of NiCO₃ into grams, using the molar mass of NiCO₃:

• NiCO₃ Molar Mass = 118.702 g/mol

• 19.9 mol * 118.702 g/mol = 2365.0 g