Question

5. Find the equation of a circle whose center is at (5, -8) and radius 8.

Answer 1

`x^(2) + y^(2) -10x -16y + 39`

Step-by-step explanation:-

The equation used to find the equation of circle is :-

`(x-a)^(2) + (y-b)^(2) = radius^(2)`

'a' means the x coordinate of the circle, 'b' means y coordinate of the circle.

In the question, it's given that the coordinates of the circle are (5, -8) and radius is 8cm.

So, 'a' will be 5 and 'b' will be -8

So,

`(x-5)^(2) + (y--8)^(2) = 8^(2)`

`(x-5)^(2) + (y+8)^(2) = 64`

`x^(2) - 10x + 25 + y^(2) - 16y + 64`

`x^(2) + y^(2) -10x -16y + 64 - 25`

=
`x^(2) + y^(2) -10x -16y + 39`