Question

Muriatic acid is often used to remove rust. A solution of muriatic acid, HCl, reacts with Fe203 deposits on

industrial equipment. How many liters of 5.00 M HCl would be needed to react completely with 339 g
Fe203?

Answer 1

2.54 L

Step-by-step explanation:

Step 1: Write the balanced neutralization equation

6 HCl + Fe₂O₃ → 3 H₂O + 2 FeCl₃

Step 2: Calculate the moles corresponding to 339 g of Fe₂O₃

The molar mass of Fe₂O₃ is 159.69 g/mol.

339 g × 1 mol/159.69 g = 2.12 mol

Step 3: Calculate the moles of HCl that react with 2.12 moles of Fe₂O₃

The molar ratio of HCl to Fe₂O₃ is 6:1. The reacting moles of HCl are 6/1 × 2.12 mol = 12.7 mol

Step 4: Calculate the volume of HCl

12.7 moles are in 5.00 M (5.00 mol/L) HCl. The required volume is:

12.7 mol × 1 L/5.00 mol = 2.54 L