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How do i solve f^2+3f-5=0

User OunknownO
by
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1 Answer

3 votes

Answer:


x = (3+√(29))/(2),(3-√(29))/(2)

Explanation:

This kinda Questions can be easily done using the Quadratic formula or Shreedhacharya's Formula . Which is used to find the roots of a quadratic equation in Standard form of ax² + bx +c = 0 .

Wrt . Standard form ,


\implies x = (-b\pm √(b^2-4ac))/(2a)\\\\\implies x = (-3\pm √(3^2-4(1)(5)))/(2(1))\\\\\implies x = (-3\pm √(9+20))/(2) \\\\\implies \boxed{\boxed{ x = (3+√(29))/(2),(3-√(29))/(2)}}

This is our required answer.

User SMGhost
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