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4 votes
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3) Janel is a bungee-jumper preparing for a legally approved jump off of a bridge over water. Janel wants to just touch
the water on her jump. Janel's path of travel is represented by f(x) = 25x2 – 120x + 144. Janel will jump from the start,
z=0. How many meters will Janel travel laterally before she touches the water?

2 Answers

3 votes

So f(x) is 0


\\ \rm\hookrightarrow 25x^2-120x+144=0


\\ \rm\hookrightarrow (5x)^2-2(5x)(12)+12^2=0


\\ \rm\hookrightarrow (5x-12)^2=0


\\ \rm\hookrightarrow 5x-12=0


\\ \rm\hookrightarrow 5x=12


\\ \rm\hookrightarrow x=12/5


\\ \rm\hookrightarrow x=2.4m

User Wesley Workman
by
5.0k points
4 votes

Answer:

2.4 meters

Explanation:

Take f(x) = 0 to find lateral distance covered.

0 = 25x² - 120 + 144

=> (5x - 12)²

=> x = 12/5

=> x = 2.4 meters

User Croeck
by
4.7k points