70.1k views
2 votes
About 150 million tons of plastic waste is in the world’s oceans. If each 001/B system can clean up 10,000 tons of plastic per year, how many systems would have to be deployed to meet the Ocean Cleanup’s goal of cleaning the oceans by 2040? Write a y = mx equation to solve.

1 Answer

2 votes

Answer:

750 systems are needed in 20 years to clean 150 million tons wastes.

Explanation:

Total waste = 150 million tons

Waste cleaned each year by 1 machine = 10,000 tons

No of years from 2020 to 2040 = 20 years

Waste cleaned in 20 years by 1 machine = 20* 10,000= 200,000 tons

Machines needed in 20 years to clean 150 million tons wastes using

y= mx ( where m= number of machines)

and x is the waste cleaned in 20 years by 1 machine

150,000,000 = m 200,000

or m = 150,000,000 /200,000

m= 750

User MBH
by
4.0k points