Question

Help me with this please!!

Answer 1

Given:-

• Points C = (-7,2) →
  `\sf{(X_1,Y_1)}`
• D = (3,12) →
  `\sf{(X_2,Y_2)}`

To Find:-

• The Midpoint of CD.

Required Response:-

Let,

Midpoint of CD be (x,y).

WKT,

`\boxed{\sf{(x,y) = (X_1+X_2)/(2),(Y_1+Y_2)/(2)}}`

`→\;{\sf{(-7+3)/(2),(2+12)/(2)}}`

`→\;{\sf{(-4)/(2),(14)/(2)}}`

`→\;{\sf{-2,7}}`

The Midpoint of CD ◕➜
`\Large{\red{\mathfrak{(-2,7)}}}`

Let,

The centre be O

Radius = CO & OD

Here, C = (-7,2) →
`\sf{(X_1,Y_1)}`

O = (-2,7) →
`\sf{(X_2,Y_2)}`

`\boxed{\sf{Distance = √((X_2-X_1)²+(Y_2-Y_1)²)}}`

`→\;{\sf{√((-2+7)²+(7-2)²)}}`

`→\;{\sf{√(5²+5²)}}`

`→\;{\sf{√(25+25)}}`

`→\;{\sf{√(50)}}`

`→\;{\sf{5√2 (or) 7.07}}`

Radius of Circle ◕➜
`\Large{\red{\mathfrak{7.07}}}`

Option D.

Hope It Helps You ✌️