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(09.01)

Choose the equation below whose axis of symmetry is x = 2. (1 point)

O y=x²-2

O y = x2 - 4x + 2

O y = x2 + 4x + 2

O y=x²-4

User Crawler
by
4.2k points

2 Answers

5 votes

Answer:

y = x2 - 4x + 2 ; y=x²-4

Explanation:

User Mjspier
by
4.7k points
6 votes

Answer:

y = x2 - 4x + 2 ; y=x²-4

Explanation:

Axis of symmetry = - b /2a

y=x²-2

a = 1 ; b = - 2

x = - (-2) / 2(1)

x = 2/2 = 1

y = x2 - 4x + 2

a = 1 ; b = - 4

x = - (-4) / 2(1)

x = 4/2 = 2

y = x2 + 4x + 2

a = 1 ; b = 4

x = - 4 / 2(1)

x = - 4/2 = - 2

y=x²-4

a = 1 ; b = - 4

x = - (-4) / 2(1)

x = 4/2 = 2

User Rich Hopkins
by
4.4k points