I have attached the complete question.
Answer:
Mean; μ = 1.648
Standard deviation;σ = 0.8610
Explanation:
From the image attached, we can see that the probabilities given under the p(x) column are;
0.091
0.334
0.408
0.166
Let's find out if these values give a probability distribution.
ΣP(x) = 0.091 + 0.334 + 0.408 + 0.166
ΣP(x) ≈ 1
Their sum is approximately 1 and they are all between 0 and 1. Thus, it is a probability distribution.
Mean is found by;
μ = ΣxP(x)
From the table attached, x = 0, 1, 2, 3
Thus;
μ = (0 × 0.091) + (1 × 0.334) + (2 × 0.408) + (3 × 0.166)
μ = 1.648
Standard deviation is given by;
σ = √[Σ(x - μ)²•P(x)]
σ = √[((0 - 1.648)² × 0.091) + ((1 - 1.648)² × 0.334) + (2 - 1.648)² × 0.408) + ((3 - 1.648)² × 0.166)]
σ = 0.8610