Question

Based on the data, if Freddy had a sales promotion and anticipated 500 orders in a given week, how many of each (chicken and fish) should he order?

Answer 1

226 fishes and 274 chicken

Explanation:

Given

`n = 500` --- anticipated orders

See attachment for table

Required

Number of fish and each to order

First, we calculate the proportion of each

This calculated by dividing the number of each by the total.

From the table, we have:

`Fish = 153`

`Chicken = 186`

`Total = 339`

So, the proportion is:

`P(Fish) = (153)/(339)`

`P(Fish) = (51)/(113)`

`P(Chicken) = (186)/(339)`

`P(Chicken) = (62)/(113)`

In an anticipated order of 500, the number of order of each is:

`Fish = P(Fish) * n`

`Fish = (51)/(113) * 500`

`Fish = (51* 500)/(113)`

`Fish = (25500)/(113)`

`Fish \approx 226`

`Chicken = n - Fish` ---- Compliment rule

`Chicken \approx 500 - 226`

`Chicken \approx 274`