Question

A wave oscillates with a period of 4.25 X 10-10 s. How many waves will strike a signal detector in 3 seconds?

Answer 1

`n=7.05* 10^9` waves

Step-by-step explanation:

Given that,

A wave oscillates with a period of
`4.25* 10^(-10)\ s`

We need to find the number of waves that will strike a signal detector in 3 seconds.

We know that,

Frequency = (no. of oscillations)/time

Time period = time/(no. of oscillations)

Let there are n waves that will strike

So,

`n=(3)/(4.25* 10^(-10))\\\\=7.05* 10^9`

Hence,
`7.05* 10^9` waves will strike in 3 seconds.