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If the radius of the base of the cone, r, is 8/3 units and the height, h, is 13 units, what is the volume of the cone?

2 Answers

6 votes

Question:-

If the radius of the base of the cone, r, is
(8)/(3) units and the height, h, is 13 units, what is the volume of the cone ?

Answer:-

Given:-


\bullet Radius of the base of the cone (r) is
(8)/(3) units.


\bullet Height (h) of the cone is 13 units.

To Find:-

Volume of the cone.

Solution:-

We know,

Formula of volume of cone is
(1)/(3) πr²h

So, volume of the cone =
(1)/(3) ×
(22)/(7) ×
((8)/(3))² × 13

=
(1)/(3) ×
(22)/(7) ×
(8)/(3) ×
(8)/(3) × 13

=
(22 \: × \: 8 \: × \: 8 \: × \: 13)/(3 \: × \: 7 \: × \: 3 \: × \: 3)

=
(18304)/(189)

= 96.85 cubic units.

Volume of the cone is 96.85 cubic units. [Answer]

User Atlasologist
by
7.6k points
4 votes

Answer:

Explanation:

r = 8/3 units

h = 13 units

Volume of cone = (1/3) πr²h


= (1)/(3)* 3.14 * (8)/(3)* (8)/(3)*13\\\\= 96.76 cubic units

User Andro
by
7.5k points

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