Question

If the radius of the base of the cone, r, is 8/3 units and the height, h, is 13 units, what is the volume of the cone?

Answer 1

Question:-

If the radius of the base of the cone, r, is
`(8)/(3)` units and the height, h, is 13 units, what is the volume of the cone ?

Answer:-

Given:-

`\bullet` Radius of the base of the cone (r) is
`(8)/(3)` units.

`\bullet` Height (h) of the cone is 13 units.

To Find:-

Volume of the cone.

Solution:-

We know,

Formula of volume of cone is
`(1)/(3)` πr²h

So, volume of the cone =
`(1)/(3)` ×
`(22)/(7)` ×
`((8)/(3))²` × 13

=
`(1)/(3)` ×
`(22)/(7)` ×
`(8)/(3)` ×
`(8)/(3)` × 13

=
`(22 \: × \: 8 \: × \: 8 \: × \: 13)/(3 \: × \: 7 \: × \: 3 \: × \: 3)`

=
`(18304)/(189)`

= 96.85 cubic units.

Volume of the cone is 96.85 cubic units. [Answer]

Answer 2

Explanation:

r = 8/3 units

h = 13 units

Volume of cone = (1/3) πr²h

`= (1)/(3)* 3.14 * (8)/(3)* (8)/(3)*13\\\\= 96.76 cubic units`