Answer:
![P_2=2.6kPa](https://img.qammunity.org/2022/formulas/chemistry/high-school/fc9y9x3jm4cu5vnjo61gfzdojp99o7928w.png)
Step-by-step explanation:
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In this case, according to the Gay-Lussac's gas law, which illustrates the pressure-temperature behavior as a directly proportional relationship:
![(P_2)/(T_2)=(P_1)/(T_1)](https://img.qammunity.org/2022/formulas/chemistry/high-school/k8k2d0r9qvypdpgh1nqd926xlye5fw9ojq.png)
We can solve for the final pressure as shown below:
![P_2=(P_1T_2)/(T_1)](https://img.qammunity.org/2022/formulas/chemistry/high-school/mmlcn1tog4xoekqve5t585r60sonmukv4f.png)
Thus, we plug in the initial pressure and temperature and final temperature to obtain:
![P_2=(6.58kPa*210K)/(540K)\\\\ P_2=2.6kPa](https://img.qammunity.org/2022/formulas/chemistry/high-school/6tbyded7ytvdqymo4cpfc0cpqpdkqj847z.png)
Which is not among the choices.
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