Question

Solve the equation for all real solutions.( Solving Quadratic with Quadratic Formula)

9a^2+25a+16=a

Answer 1

-4/3

Explanation:

Answer 2

`a = -\frac43`

Explanation:

Hello!

Standard form of a quadratic:
`ax^2 + bx + c = 0`

Quadratic Equation:
`x = (-b\pm√(b^2 - 4ac))/(2a)`

Convert it to Standard Form:

• 
  `9a^2 + 25a + 16 = a`
• 
  `9a^2 + 24a + 16 = 0`

In this equation, x is replaced with a, and a is replaced with x.

Solve

• 
  `a = (-b\pm√(b^2 - 4xc))/(2x)`
• 
  `a = (-24\pm√(24^2 - 4(9)(16)))/(2(9))`
• 
  `a = (-24\pm√(576 - 576))/(18)`

• 
  `a = (-24\pm√(0))/(18)`

• 
  `a = -(24)/(18)`

• 
  `a = -\frac43`

The value of a is
`-\frac43`