Answer:
2513.41 mm³
Explanation:
Given that,
The diameter of ball 1 = 39.5 mm
Radius of ball 1 = 19.75 mm
The volume of ball 1 is :
![V_1=(4)/(3)\pi r^3\\\\=(4)/(3)\pi * 19.75^3\\\\=32269.32\ mm^3](https://img.qammunity.org/2022/formulas/mathematics/high-school/c35pxhlulzp15jdbpgyt0o6dhmo5ppetzh.png)
The diameter of ball 2, = 40.5 mm
Radius = 20.25 mm
Volume of ball 2,
![V_2=(4)/(3)\pi * 20.25^3\\\\=34782.73\ mm^3](https://img.qammunity.org/2022/formulas/mathematics/high-school/u4ygt1iqm790vuwftjsq1loggvl2djgz7d.png)
Difference in volume = V₂ - V₁
= 34782.73 - 32269.32
= 2513.41 mm³
So, the difference in volume of the ball is equal to 2513.41 mm³.