Question

A basketball inflated to a pressure of 2.25 atm is increased in temperature from 275 K to 317 K.What will be the new pressure, in torr, if the volume remains constant?

Answer 1

`P_2=1971.2torr`

Step-by-step explanation:

Hello there!

In this case, by recalling the Gay-Lussac's gas law, as a directly proportional relationship between pressure and temperature, we can write:

`(P_2)/(T_2) =(P_1)/(T_1)`

Thus, by solving for the required final pressure, in atmospheres first, we solve for P2 as follows:

`P_2 =(P_1T_2)/(T_1)\\\\P_2=(2.25atm*317K)/(275K)\\\\P_2=2.59atm`

Which in Torricelli is:

`P_2=2.59atm *(760torr)/(1atm)\\\\P_2=1971.2torr`

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