Question

PLS HELP.

A rope breaks when the speed of a 0.309 kg mass moving in a circle of radius of 0.429 m reaches 12.9 m/s
how much tension is in the strings when it breaks?
unti=n

Answer 1

Answer: 119.9

Step-by-step explanation:

F = (mv^2)/r

Here we know m (0.309kg), v (12.9m/s) and r (0.429m)

So F = (0.309*12.9^2)/0.429 = 119.861748

Answer 2

120 works for acellus