Question

Given x^2 + y^2 = 16, find

name:
center:
Domain:
Range:
x-int
y-int
​

Answer 1

The equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 16 ← is the equation of a circle

centre (0, 0 ) and r = \sqrt{16}16 = 4

The circle therefore intercepts the x- axis at (4, 0 ) and (4, 0 )

and intercepts the y- axis at (0, - 4 ) and (0, 4 )

Answer 2

see explanation

Explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 16 ← is the equation of a circle

centre (0, 0 ) and r =
`√(16)` = 4

The circle therefore intercepts the x- axis at (4, 0 ) and (4, 0 )

and intercepts the y- axis at (0, - 4 ) and (0, 4 )

Domain is - 4 ≤ x ≤ 4

range is - 4 ≤ y ≤ 4

x- intercepts are x = - 4, x = 4

y- intercepts are - 4, 4