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4. How many moles of Ca(HCO3)2 are present in 4.6 liters of a 3.5 molarity solution?
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Jun 1, 2022
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4. How many moles of Ca(HCO3)2 are present in 4.6 liters of a 3.5 molarity
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NicolasW
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Multiply the volume by molarity to get moles.
3.5 M • 4.6 L = 16.1 mol Ca(HCO3)2
Kieran McClung
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Jun 7, 2022
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