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4. How many moles of Ca(HCO3)2 are present in 4.6 liters of a 3.5 molarity solution?
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4. How many moles of Ca(HCO3)2 are present in 4.6 liters of a 3.5 molarity
solution?

User NicolasW
by
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1 Answer

2 votes
Multiply the volume by molarity to get moles.

3.5 M • 4.6 L = 16.1 mol Ca(HCO3)2
User Kieran McClung
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