Question

A 2,000 kg freight train is traveling on the railroad tracks from Birmingham to Mobile. It traveling at a speed of 25 m/sec. What is the kinetic energy of this train?

Answer 1

The kinetic energy of the 2,000 kg freight train traveling at 25 m/sec is 625,000 Joules or 625 kJ, calculated using the formula KE = 0.5 × mass × velocity².

Step-by-step explanation:

The kinetic energy (KE) of the freight train can be calculated using the formula for kinetic energy, KE = ½mv², where m is the mass of the object and v is the velocity. In this case, the mass (m) of the freight train is 2,000 kg and the velocity (v) is 25 m/sec. Thus, the kinetic energy of the train is KE = ½(2,000 kg)(25 m/sec)².

Calculating this, we get KE = 0.5 × 2,000 kg × (25 m/sec)² = 0.5 × 2,000 kg × 625 (m²/sec²) = 625,000 Joules or 625 kJ.

So, the kinetic energy of the 2,000 kg freight train traveling at a speed of 25 m/sec is 625 kJ.

Answer 2

The correct answer is "625,000 J".

Step-by-step explanation:

The given values are:

Mass,

m = 2,000 kg

Speed,

v = 25 m/sec

As we know,

⇒
`Kinetic \ energy=(1)/(2) (mass * speed^2)`

Or,

⇒
`K.E=(1)/(2)(mv^2)`

On substituting the values, we get

⇒
`=(1)/(2)(2,000* 25^2)`

⇒
`=1000* 625`

⇒
`=625,000 \ J`