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I’m circle a shown, secant de and tangent dg are drawn. It is known that angle bac equals 72 degrees and arc be equals 96 degrees

User Marykate
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1 Answer

4 votes

Answer:


m(BC) = 72^\circ


m\angle EBC = 168^\circ

Explanation:

Given


m\angle BAC = 72


m(BE) = 96

See attachment for circle

Required

Determine

(a) Measure of BC

(b) Measure of EBC

(a) Measure of BC

From the attachment, we can see that:


m(BC) = m\angle BAC because they belong to the same sector

This gives:


m(BC) = 72^\circ

(b) Measure of EBC

From the attachment, we can see that:


m\angle EBC = m(EB) +m(BC)

Where


m(EB) = m(BE) =96^\circ

So, we have:


m\angle EBC = 96^\circ + 72^\circ


m\angle EBC = 168^\circ

I’m circle a shown, secant de and tangent dg are drawn. It is known that angle bac-example-1
User Priyadarshan
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4.5k points