Question

A certain oscillator satisfies the equation of motion Initially the particle is at

the point x = √3 when it is projected towards the origin with speed 2.

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Answer 1

in simple harmonic motion, the formula for finding amplitude is:

a = -ω^2 x

where, a=amplitude, ω= angular frequency, x= Displacement

Step-by-step explanation:

Answer 2

The position of the particle at any given time t is given by x = √3 Cos 2t - Sin 2t.

To solve the equation of motion x+4x=0, we can use the general solution for simple harmonic motion, which is x = A Cos 2t + B Sin 2t, where A and B are arbitrary constants.

Given the initial conditions x = √3 and speed = 2.2, we can substitute these values into the general solution.

Plugging in the values, we get x = √3 Cos 2t - Sin 2t.

Therefore, the position of the particle at any given time t is given by x = √3 Cos 2t - Sin 2t.