Question

Calculate the concentration of the solution produced when a 3.2g of sodium chloride is

issolved in 8dm of water.

Answer 1

The concentration of the 3.2 g of sodium chloride in 8 dm³ of water is 6.845 × 10⁻³ M

Step-by-step explanation:

The concentration of a solution is given as either the ratio of mass to volume, or the ratio of volume to volume or as molarity

`Concentration, C = (Mass)/(Volume) = (Volume)/(Volume) = (Number \ of \ moles )/(Liters \ of \ solution)`

The number of moles present in 3.2 g of sodium chloride, 'n', is given as follows;

`n = (Mass)/(Molar \ mass)`

The molar mass of sodium chloride, NaCl = 58.44 g/mol

n = 3.2 g/58.44 g/mol = 0.0547570157 moles

8 dm³ = 8 Liters

Therefore, the concentration, C = 0.0547570157 moles/(8 liters) = 6.845 × 10⁻³ M

The concentration of the 3.2 g of sodium chloride in 8 dm³ of water = 6.845 × 10⁻³ Molar solution.