The product of two consecutive integers is zero, find the integers. Show work

Question

asked Jul 28, 2022 224k views

1 Answer

Brklyn · Answer 1 · 2022-08-03T09:48:41+0000

Answer:

0,1

Explanation:

Let n represent the first interger. and n+1 represent the next interger.

n * (n + 1) = 0

${n}^(2) + n = 0$

Complete the square.

$( (n)/(2) {)}^(2) = \frac{ {n}^(2) }{4}$

${n}^(2) +n + \frac{ {n}^(2) }{4} = \frac{ {n}^(2) }{4}$

$(n + (n)/(2) ) {}^(2) = \frac{n {}^(2) }{4}$

Take the square root.

(n + (n)/(2) ) = (n)/(2)

n = 0

Plug 0 in for 0+1.

0 + 1 = 1

So the consective intergers are 0,1.