Answer:
m = 51.93 grams
Step-by-step explanation:
Given that,
Energy added, Q = 747 joules
The specific heat capacity of Aluminium, c = 0.899 J/g°C
The temperature goes from 105.0°C to 121.0°C.
Let the mass of the aluminum sample is m. We know that, the heat added to the system is given by :
![Q=mc\Delta T\\\\m=(Q)/(c\Delta T)\\\\m=(747)/(0.899 * (121-105))\\\\m=51.93\ g](https://img.qammunity.org/2022/formulas/chemistry/college/8c3u3xiwm8sdyfgdb6pumx7247zucsj5y5.png)
So, the mass of the sample is 51.93 grams.