Answer:
(0.109 ; 0.171)
Explanation:
Phat ± Zcritical * sqrt[(phat(1 - phat)) / n]
Phat = 0.14 ; n = 348
1 - phat = 1 - 0.14 = 0.86
Zcritical at95% = 1.96
0.14 ± 1.96*sqrt[(0.14(0.86)) / 348]
0.14 ± 0.0308117
Lower boundary (0.14 - 0.0308117) =
Upper boundary = (0.14 + 0.0308117)
Hence, interpreting the meaning of 95% confidence interval ; this means that there is 95% confidence that the average proportion of trucks that have driven too may hours lies within the interval above.