Question

PLEASE HELP 20 PTS

what is the percent by volume of isopropyl alcohol in a solution that contains 24 mL of isopropyl alcohol in 1.1 L of water?

Answer 1

`2.18\%`

Step-by-step explanation:

Volume of isopropyl alcohol = 24 mL

Volume of water = 1.1 L

Percentage of isopropyl alcohol is given by

`\frac{\text{Volume of isopropyl alcohol}}{\text{Volume of isopropyl alcohol+Volume of water}}* 100\\= (24* 10^(-3))/(1.1+2.4* 10^(-3))* 100\\ =2.18\%`

The percent by volume of isopropyl alcohol in the given solution is
`2.18\%`.