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At the same temperature and pressure, 15L of CO2 gas has the same amount of molecules as what volume of N2 gas?

User Stephband
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1 Answer

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Answer: 15 L of
N_2 gas will have same numer of molecules as 15L of
CO_2 gas at the same temperature and pressure,

Step-by-step explanation:

According to avogadro's law, equal moles of gases occupy equal volume at same conditions of temperature and pressure.


\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}


\text{Number of moles of} CO_2=(15L)/(22.4L/mol)=0.67mol


1 mole of CO_2 contains=
6.022* 10^(23) molecules of
CO_2

Thus 0.67 moles of
CO_2 contains=
(6.022* 10^(23))/(1)* 0.67=4.03* 10^(23) molecules

Now molecules of
N_2 = molecules of
CO_2 =
4.03* 10^(23)


6.023* 10^(23) molecules of
N_2 = 22.4 L

Now
4.03* 10^(23) molecules of
N_2 =
(22.4)/(6.023* 10^(23))* 4.03* 10^(23)=15L

User Theodore Tsirpanis
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