Question

Calculate the temperature of a gas when it is expanded to 5.25L. The gas originally occupies 3.90L of space at 252K.

Answer 1

`T_2=339K`

Step-by-step explanation:

Hello there!

In this case, according to the Charles' gas law as way to understand the volume-temperature as a directly proportional relationship for this problem, we can write:

`(T_2)/(V_2)=(T_1)/(V_1)`

Thus, given the initial temperature and volume and the final volume, we are able to calculate the final temperature as follows:

`T_2=(T_1V_2)/(V_1) \\\\T_2=(252K*5.25L)/(3.90L)\\\\T_2=339K`

Best regards!