Question

The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparallel to a uniform magnetic field of 50.0 T in which it lies. Question 5. The magnitude and direction of the total magnetic moment is ……to the area vector.

Answer 1

`M= 0.4 Am^2`

Step-by-step explanation:

From the question we are told that:

Number of turns
`N=5`
`N=5`

Conductor each with side length
`L=0.2m`

Current
`I=2A`

Magnetic field
`B=50.0T`

Generally the equation for the total magnetic moment M is mathematically given by

`M = current * area`

`M= I * A`

`M = 2 * (5* 0.2*0.2)`

`M = 2 * 0.2`

`M= 0.4 Am^2`