Question

Solve the equation for all real solutions.
3c^+4c+8=-6c

Answer 1

c = -4/3, -2

Explanation:

3c^2+4c+8=-6c

3c^2+6c+4c+8=0

3c(c+2) + 4(c+2)=0

(3c+4)(c+2)=0

3c+4=0

c=-4/3

c+2=0

c=-2