Final answer:
Using the combined gas law, the final volume of a gas undergoing changes in temperature and pressure is calculated to be 11.25 L.
Step-by-step explanation:
The student's question involves finding the final volume of a gas when the temperature and pressure change. This is a classic application of the combined gas law, which is relevant in Chemistry.
The combined gas law equation is:
(P₁ x V₁) / T₁ = (P₂ x V₂) / T₂, where P is pressure, V is volume, and T is temperature (in Kelvin).
In the given scenario, we have V₁ = 10 L, P₁ = 1.5 atm, T₁ = 200 K, T₂ = 300 K, and P₂ = 2 atm.
We must solve for V₂.
Substituting the known values into the combined gas law equation yields (1.5 atm x 10 L) / 200 K = (2 atm x V₂) / 300 K.
Solving for V₂ gives us V₂ = (1.5 atm x 10 L x 300 K) / (200 K x 2 atm), which simplifies to V₂ = 11.25 L.
Thus, the final volume of the gas at 300 K and 2 atm of pressure would be 11.25 L.