220k views
5 votes
We intend to estimate the average driving time of a group of commuters. From a previous study, we believe that the average time is 42 minutes with a standard deviation of 10 minutes. We want our 90 percent confidence interval to have a margin of error of no more than plus or minus 2 minutes. What is the smallest sample size that we should consider

User Tarulen
by
8.1k points

1 Answer

4 votes

Answer:

The smallest sample size that we should consider is 68.

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1 - 0.9)/(2) = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of
1 - \alpha.

That is z with a pvalue of
1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such


M = z(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation of 10 minutes.

This means that
\mu = 10

What is the smallest sample size that we should consider?

This is n for which M = 2. So


M = z(\sigma)/(√(n))


2 = 1.645(10)/(√(n))


2√(n) = 1.645*10


√(n) = 1.645*5


(√(n))^2 = (1.645*5)^2


n = 67.7

Rounding up:

The smallest sample size that we should consider is 68.

User Kelvin Hu
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories