220k views
5 votes
We intend to estimate the average driving time of a group of commuters. From a previous study, we believe that the average time is 42 minutes with a standard deviation of 10 minutes. We want our 90 percent confidence interval to have a margin of error of no more than plus or minus 2 minutes. What is the smallest sample size that we should consider

User Tarulen
by
3.5k points

1 Answer

4 votes

Answer:

The smallest sample size that we should consider is 68.

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1 - 0.9)/(2) = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of
1 - \alpha.

That is z with a pvalue of
1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such


M = z(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation of 10 minutes.

This means that
\mu = 10

What is the smallest sample size that we should consider?

This is n for which M = 2. So


M = z(\sigma)/(√(n))


2 = 1.645(10)/(√(n))


2√(n) = 1.645*10


√(n) = 1.645*5


(√(n))^2 = (1.645*5)^2


n = 67.7

Rounding up:

The smallest sample size that we should consider is 68.

User Kelvin Hu
by
3.6k points