3.8k views
5 votes
Two harmonic waves moving in the same direction are described by y1(x,t)=10.2sin(4x-700t) and y2(x,t)=10.2sin(4x-700t-7.9). What is the amplitude of the resultant wave at interference

1 Answer

7 votes

Answer:

14.42 units

Step-by-step explanation:

The waves are given as follows :


y_1(x,t)=10.2\sin(4x-700t)\\\\y_2(x,t)=10.2\sin(4x-700t-7.9)

We need to find the amplitude of the resultant wave at interference. Let it be A. So,


A=√(10.2^2+10.2^2) \\\\=14.42\ units

So, the amplitude of the resultant wave is equal to 14.42 units.

User Igorti
by
7.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.