Question

What is an equation of the line that passes through the points (−3,3) and (3,−7)?

Answer 1

`y=-(5)/(3) x+8`

Explanation:

Slope=
`(y_(1)-y_(2) )/(x_(1) -x_(2) )`

=
`(3-(-7))/(-3-3)`

=
`(10)/(-6)`

=
`-(5)/(3)`

So
`3=-(5)/(3) *(-3)+b`, b=8

So
`y=-(5)/(3) x+8`

Answer 2

`y=-(5)/(3)x-2`

Explanation:

line equation in general y = mx + b

m is the slope, and

b is the y-intercept

3=-3m+b

-7=3m+b

if we plus this two equations

3-7=2b

2b=-4

b=-2

3m=b-3=-5

m=-5/3

So,

`y=-(5)/(3)x-2`