228k views
0 votes
Consider the quadratic equation x2+8x+9=0. Which of the following is the correct form after substituting a, b, and c into the Quadratic Formula?

2 Answers

0 votes

As given

  • x²+8x+9=0

General equation

  • Ax²+Bx+C

On comparing

  • A=1
  • B=8
  • C=9
User Typetetris
by
7.4k points
3 votes

Answer:

x²+8x+9=0

Comparing above equation with ax²+bx +c

we get

a=1

b=8

c=9

quadratic equation is


x = \frac{ - 8± \sqrt{ {8}^(2) - 4×1×9} }{2*1}


x = ( -8± √( 64-36) )/(2)

2x+8=±
\sqrt{ {28}}

taking + ve

2x=
\sqrt{ {28}}-8

x=
2\sqrt{ {7}}-8/2

x=
\sqrt{ {7}}-4

taking -ve

2x=-
\sqrt{ {28}}-8

x=-
2\sqrt{ {7}}-8/2

x=-
\sqrt{ {7}}-4

User Netpoetica
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories