Question

Water is flowing at 4.0 m/s in a circular pipe. If the diameter of the pipe decreases to 1/2 of its former value, what is the velocity of the water?

Answer 1

v₂ = 16 m/s

Step-by-step explanation:

We can use the continuity equation, which is as follows:

`A_1v_1 = A_2v_2\\`

where,

A₁ = Area of inlet = πd²/4

A₂ = Area of outlet = π(d/2)²/4 = πd²/16

v₁ = velocity at inlet = 4 m/s

v₂ = velocity at outlet = ?

Therefore,

`((\pi d^2)/(4))(4\ m/s)=((\pi d^2)/(16))v_2\\\\`

v₂ = 16 m/s