Answer:
2(4 + 3i) / 5
Explanation:
(6 + 2i) (3 + i) / (3 - i) (3 + i)
=> 18 + 12i + 2i² / 9 - i²
=> 16 + 12i / 10
=> 8 + 6i / 5
=> 2(4 + 3i) / 5
(6 +2i) / (3-i) = (6+2i)/(3-i) x (3+i)/(3+i) = (6+2i)(3+i) / (3-i)(3+i) = 6(3+i)+2i(3+i) / (3)^2-(i)^2 = 18+6i+6i+2i^2 / 9-i^2 = 18+12i+2i^2 / 9-i^2 = 6+12i+2i^2 / 3-i^2 = 2+12i+2i^2 / 1-i^2 = 2+12i+2 / 1 = 4+12ianswer.
1.6m questions
2.0m answers