Question

The work of a student to solve the equation 3(3y − 8) = 10 + 3y is shown below:

Step 1: 3(3y − 8) = 10 + 3y
Step 2: 6y − 5 = 10 + 3y
Step 3: 3y − 5 = 10
Step 4: 3y = 15
Step 5: y = 5

In which step did the student first make an error and what is the correct step?

Step 2: 9y − 24 = 10 + 3y
Step 2: 6y + 11 = 10 + 4y
Step 3: 6y − 8 = 3(6 + y)
Step 3: 3(3y − 8) = 7 + y

Answer 1

Step 2 9y - 24 = 10 + 3y because 3 times 3y its not 6y nor is 3 times 8 equal to 5