Question

A car traveling at 60km/h undergoes uniform acceleration at a rate of 2/ms^2 until is velocity reached 120km/h determine the distance traveled and the time taken to make the distance

Answer 1

Step-by-step explanation:

Given that,

Initial speed of a car, u = 60 km/h = 16.67 m/s

Acceleration, a = 2m/s²

Final speed, v = 120 km/h = 33.33 m/s

We need to find the distance traveled and the time taken to make the distance.

acceleration = rate of change of velocity

`a=(v-u)/(t)\\\\t=(v-u)/(a)\\\\t=(33.33 -16.67 )/(2)\\\\t=8.33\ s`

let the distance be d.

`d=(v^2-u^2)/(2a)\\\\d=(33.33^(2)-16.67^(2))/(2(2))\\\\d=208.25\ m`

Hence, the distance traveled and the time taken to make the distance is 208.25 m and 8.33 seconds respectively.