What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)

asked Jul 23, 2023 169k views

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Answer:

Explanation:

Using the distance formula,

$AB=\sqrt{(-11-(-7))^(2)+(4-8)^(2)}=√(16+16)=4√(2)\\AC=\sqrt{(-11-(-4))^(2)+(4-4)^(2)}=7\\BC=\sqrt{(-7-(-5))^(2)+(8-4)^(2)}=√(4+16)=2√(5)\\\\$

So the perimeter is
4√(2)+7+2√(5)

JineshEP answered Jul 30, 2023

5.3k points

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