Final answer:
The actual molar concentration of the H₂O₂ solution is calculated using titration data and stoichiometry, resulting in a concentration of 0.0756 M.
Step-by-step explanation:
To determine the actual molar concentration of the H₂O₂ solution, we can use the following stoichiometry steps based on the information given and the balanced chemical equation for the reaction between H₂O₂ and KMnO₄.
- Calculate the moles of KMnO₄ used in the titration: moles = Molarity x Volume = 0.01411 M x 0.03217 L = 4.537 x 10-4 moles.
- The balanced equation for the reaction is 2MnO₄- + 6H+ + 5H₂O₂ → 2Mn2++ 8H₂O + 5O₂, which means 5 moles of H₂O₂ react with 2 moles of KMnO₄.
- Calculate the moles of H₂O₂: (5/2) x 4.537 x 10-4 moles = 1.134 x 10-3 moles
- Calculate the molarity of the diluted solution: Moles / Volume = 1.134 x 10-3 moles / 0.1 L = 0.01134 M
- Calculate the molarity of the original solution before dilution: Molarity after dilution x Dilution Factor = 0.01134 M x (100 mL / 1.5 mL) = 0.0756 M
The actual molar concentration of the H₂O₂ solution in the drugstore bottle is 0.0756 M.