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HELP PLEASE and show work

HELP PLEASE and show work-example-1
User Nodrog
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1 Answer

5 votes

Answer:


\boxed{\stackrel{\Large\frown}{PQS}\:= 222°}

Step-by-step explanation:

Since
\overline{PR} is a diameter, arc
\stackrel{\Large\frown}{PQR}\:= 180°.

Given that
\angle{SUR} = 42° is a subtended central angle by two diameters,


\stackrel{\large\frown}{RS} \:= 42°.

Using the rule of arcs,
\stackrel{\Large\frown}{PQR} + \stackrel{\large\frown}{RS} \: = \: \stackrel{\Large\frown}{PQS}


180° + \: 42° = \: \stackrel{\Large\frown}{PQS}


222° = \: \stackrel{\Large\frown}{PQS}


\stackrel{\Large\frown}{PQS} \: = \: 222°

User Wonsuc
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