Given Equation:-
To find:-
Solution:-
Let this be Equation one :-
2x + 2y = 20 . . . . . . ( 1 )
and this be Equation two :-
3x = 2y. . . . . . . . . . . . .( 2 )
Simplifying equation one:-
↝ 2x + 2y = 20
↝ 2 (x + y) = 20
↝ x + y = 20/2
↝ x + y = (10 × 2)/2
↝ x + y = (10 ×1)/1
↝ x + y = 10
↝y = 10 - x
Put this value of y in Equation two:-
↦ 3x = 2y
↦ 3x = 2(10 - x)
↦ 3x = 2(10) - 2(x)
↦ 3x = 20 - 22x
↦ 3x + 2x = 20
↦ 5x = 20
↦ x = 20/5
↦ x = (4 × 5)/5
↦ x = (4 × 1)/1
↦ x = 4
Now Let's ind Value of y:-
put value of x in the equation one but simplified form.
↝ y = 10 - x
↝ y = 10 - 4
↝ y = 6
Now let Verify either the value of x and y:- .
↦ 2x + 2y = 20
put value of x and y in this equation.
↦ 2(4) + 2(6) = 20
↦ 2 × 4 + 2(6) = 20
↦ 8 + 2(6) = 20
↦ 8 + 2 × 6 = 20
↦ 8 + 12 = 20
↦ 20 = 20
LHS = RHS
.°. First equation is verified ✓.
Now Let's Verify 2 equation:
↝ 3x = 2y
put value of x and y.
↝3(4) = 2(6)
↝ 3 × 4 = 2(6)
↝12 = 2 × 6
↝12 = 12
LHS = RHS
.°. Second equation is verified ✓.
___________________♡~
Required Answer :-
x = 4
y = 6