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Given f(x)=3x^3+kx-8, and the remainder when f(x) is divided by x-3 is 43, then what is the value of k?
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Given f(x)=3x^3+kx-8, and the remainder when f(x) is divided by x-3 is 43, then what is the value of k?

User Anja Ishmukhametova
by
8.0k points

1 Answer

3 votes

Answer:

k= - 10

Explanation:

43 = - 8 +3(27+k)

3(27+k) = 51

27 + k = 17

k = - 10

Given f(x)=3x^3+kx-8, and the remainder when f(x) is divided by x-3 is 43, then what-example-1
User Mcestone
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