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The equation is 2x + 2y = 20 and 3x = 2y. You have to solve it with substitution.

The equation is 2x + 2y = 20 and 3x = 2y. You have to solve it with substitution.-example-1
User Exfizik
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2 Answers

3 votes

Answer:

3x+y=15, x+2y=20

Explanation:

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

User Shreddd
by
3.2k points
7 votes

Given Equation:-

  • 2x + 2y = 20
  • 3x = 2y.

To find:-

  • Value of x
  • Value of y

Solution:-

Let this be Equation one :-

2x + 2y = 20 . . . . . . ( 1 )

and this be Equation two :-

3x = 2y. . . . . . . . . . . . .( 2 )

Simplifying equation one:-

↝ 2x + 2y = 20

↝ 2 (x + y) = 20

↝ x + y = 20/2

↝ x + y = (10 × 2)/2

↝ x + y = (10 ×1)/1

↝ x + y = 10

↝y = 10 - x

Put this value of y in Equation two:-

↦ 3x = 2y

↦ 3x = 2(10 - x)

↦ 3x = 2(10) - 2(x)

↦ 3x = 20 - 22x

↦ 3x + 2x = 20

↦ 5x = 20

↦ x = 20/5

↦ x = (4 × 5)/5

↦ x = (4 × 1)/1

↦ x = 4

Now Let's ind Value of y:-

put value of x in the equation one but simplified form.

↝ y = 10 - x

↝ y = 10 - 4

↝ y = 6

Now let Verify either the value of x and y:- .

↦ 2x + 2y = 20

put value of x and y in this equation.

↦ 2(4) + 2(6) = 20

↦ 2 × 4 + 2(6) = 20

↦ 8 + 2(6) = 20

↦ 8 + 2 × 6 = 20

↦ 8 + 12 = 20

↦ 20 = 20

LHS = RHS

.°. First equation is verified ✓.

Now Let's Verify 2 equation:

↝ 3x = 2y

put value of x and y.

↝3(4) = 2(6)

↝ 3 × 4 = 2(6)

↝12 = 2 × 6

↝12 = 12

LHS = RHS

.°. Second equation is verified ✓.

___________________♡~

Required Answer :-

x = 4

y = 6