Answer:
14
Explanation:
Given the indicinal expression 64^5/6 + 27^2/3 - 81^3/4
According to indices;
![a^(m/n) = (\sqrt[n]{a}) ^m](https://img.qammunity.org/2022/formulas/mathematics/high-school/f2hf4u7t63ugyz78aravuhumpjbmxfqb2m.png)
Applying this to the question
![64^(5/6) \\= (\sqrt[6]{64}) ^5\\= 2^5= 32](https://img.qammunity.org/2022/formulas/mathematics/high-school/t3d93wzqns2n4fq8n150fug7d2x6ortcbg.png)
Similarly
![27^(2/3)\\= (\sqrt[3]{27}) ^2\\= 3^2\\= 9\\](https://img.qammunity.org/2022/formulas/mathematics/high-school/mzokkwoy0fem7rq0gr8bk7tmnuzmwppc1i.png)
Also;
![81^(3/4)\\= (\sqrt[4]{81}) ^3\\= 3^3\\= 27](https://img.qammunity.org/2022/formulas/mathematics/high-school/hsg9pxm5hqgp04mjg73t6ph9one97ed22d.png)
Substitute inti the original equation
64^5/6 + 27^2/3 - 81^3/4
= 32 + 9- 27
= 41 - 27
= 14
Hence the required answer is 14