Question

The lengths of the sides of two squares are

4cm and 6 cm. Find, in its simplest form,
the ratio of the ir:
6.
perimeters.
b)
a)
areas.​

Answer 1

a. Ratio of their perimeters = 3/2 or 1.5

b. Ratio of their areas = 9/4 or 2.25

Step-by-step explanation:

Let the first square be S1.

Let the second square be S2.

Given the following data;

Length of sides of S1 = 4cm

Length of sides of S2 = 6cm

To find the ratio of their perimeters and areas.

I. For perimeter of S1;

Perimeter of square = 4 * Length of sides

Perimeter of S1 = 4 * 4

Perimeter of S1 = 16 cm

II. For perimeter of S2;

Perimeter of S2 = 4 * 6

Perimeter of S2 = 24 cm

a. The ratio of their perimeters;

Ratio = S2/S1

Ratio = 24/16

Ratio = 3/2

Ratio = 1.5

III. For area of S1;

Area of square = L²

Area of S1 = 4²

Area of S1 = 16 cm²

IV. For area of S2;

Area of S1 = 6²

Area of S1 = 36 cm²

b. The ratio of their areas;

Ratio = S2/S1

Ratio = 36/16

Ratio = 9/4

Ratio = 2.25