Question

) A different rectangle has area 12a² and perimeter 14a

What are the dimensions of this rectangle?
Dimensions:
. by​

Answer 1

l = 4a and b = 3a

Explanation:

Given that,

The area of the rectangle, A = 12a²

Perimeter, P = 14a

The area and perimeter of a rectangle are given by :

A = lb

12a² = lb ....(1)

P = 2(l+b)

14a = 2(l+b) ....(2)

We need to solve equations (1) and (2). After solving we find that.

l = 4a and b = 3a

Hence, the dimensions of this rectangle are 4a and 3a.